(x-4)(25x^2+40x+12)=0

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Solution for (x-4)(25x^2+40x+12)=0 equation: 


Simplifying
(x + -4)(25x2 + 40x + 12) = 0

Reorder the terms:
(-4 + x)(25x2 + 40x + 12) = 0

Reorder the terms:
(-4 + x)(12 + 40x + 25x2) = 0

Multiply (-4 + x) * (12 + 40x + 25x2)
(-4(12 + 40x + 25x2) + x(12 + 40x + 25x2)) = 0
((12 * -4 + 40x * -4 + 25x2 * -4) + x(12 + 40x + 25x2)) = 0
((-48 + -160x + -100x2) + x(12 + 40x + 25x2)) = 0
(-48 + -160x + -100x2 + (12 * x + 40x * x + 25x2 * x)) = 0
(-48 + -160x + -100x2 + (12x + 40x2 + 25x3)) = 0

Reorder the terms:
(-48 + -160x + 12x + -100x2 + 40x2 + 25x3) = 0

Combine like terms: -160x + 12x = -148x
(-48 + -148x + -100x2 + 40x2 + 25x3) = 0

Combine like terms: -100x2 + 40x2 = -60x2
(-48 + -148x + -60x2 + 25x3) = 0

Solving
-48 + -148x + -60x2 + 25x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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